Make a single problem from div3
I didn't actually submit this one, I just got tired and gave up on the div... I'll simulate it later.
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Codeforces Round 981 (Div. 3)/A. Sakurako and Kosuke.cpp
Normal file
106
Codeforces Round 981 (Div. 3)/A. Sakurako and Kosuke.cpp
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#include <bits/stdc++.h>
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using namespace std;
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#define V vector
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#define rmin(a, b) a = min(a, b)
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#define rmax(a, b) a = max(a, b)
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#define rep(i, lim) for (size_t i = 0; i < (lim); i++)
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#define nrep(i, s, lim) for (size_t i = s; i < (lim); i++)
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#define repv(i, v) for (auto &i : (v))
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#define fillv(v) for (auto &itr_ : (v)) { cin >> itr_; }
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#define sortv(v) sort(v.begin(), v.end())
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#define all(v) (v).begin(), (v).end()
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using vi = vector<int>;
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using vvi = vector<vi>;
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using vvvi = vector<vvi>;
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using vvvvi = vector<vvvi>;
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using ll = long long;
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using vl = vector<ll>;
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using vvl = vector<vl>;
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using vvvl = vector<vvl>;
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using vvvvl = vector<vvvl>;
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template<class v>
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auto operator<<(ostream &os, const vector<v> &vec)->ostream& {
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os << vec[0];
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for (size_t i = 1; i < vec.size(); i++) {
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os << ' ' << vec[i];
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}
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os << '\n';
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return os;
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}
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template<class v>
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auto operator>>(istream &is, vector<v> &vec)->istream& {
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for (auto &i : vec) {
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is >> i;
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}
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return is;
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}
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template<class v>
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auto operator<<(ostream &os, const vector<vector<v>> &vec)->ostream& {
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for (auto &i : vec) {
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os << i[0];
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for (size_t j = 1; j < i.size(); j++) {
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os << ' ' << i[j];
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}
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os << '\n';
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}
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return os;
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}
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template<class v>
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auto operator>>(istream &is, vector<vector<v>> &vec)->istream& {
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for (auto &i : vec) {
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for (auto &j : i) {
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is >> j;
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}
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}
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return is;
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}
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int main()
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{
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ios::sync_with_stdio(false);
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cin.tie(nullptr);
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int high = 0;
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V<int> ind;
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V<string> player;
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int now = 0;
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V<string> players = {
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"Sakurako",
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"Kosuke"
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};
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int i = 1;
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int x = 0;
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while (high <= 100) {
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int mov = i * 2 - 1;
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x += (now ? mov : -mov);
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if (abs(x) > high) {
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high = abs(x);
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ind.push_back(high);
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player.push_back(players[now]);
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}
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now ^= 1;
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i++;
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}
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int t;
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cin >> t;
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while (t--) {
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int n;
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cin >> n;
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int it = upper_bound(ind.begin(), ind.end(), n) - ind.begin();
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cout << player[it] << '\n';
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}
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}
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