Codeforces-solutions/Codeforces Round 1052 (Div. 2)/E. Yet Another MEX Problem.cpp

185 lines
4.2 KiB
C++

/* Problem URL: https://codeforces.com/contest/2146/problem/E */
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
template <class T, class comp = less<>>
using ordered_set = tree<T, null_type , comp , rb_tree_tag , tree_order_statistics_node_update>;
#define V vector
#define rmin(a, b) a = min(a, b)
#define rmax(a, b) a = max(a, b)
#define rep(i, lim) for (int i = 0; i < (lim); i++)
#define nrep(i, s, lim) for (int i = s; i < (lim); i++)
#define repv(i, v) for (auto &i : (v))
#define fillv(v) for (auto &itr_ : (v)) { cin >> itr_; }
#define sortv(v) sort(v.begin(), v.end())
#define all(v) (v).begin(), (v).end()
using vi = vector<int>;
using vvi = vector<vi>;
using vvvi = vector<vvi>;
using vvvvi = vector<vvvi>;
using ll = long long;
using vl = vector<ll>;
using vvl = vector<vl>;
using vvvl = vector<vvl>;
using vvvvl = vector<vvvl>;
template<class v>
auto operator<<(ostream &os, const vector<v> &vec)->ostream& {
os << vec[0];
for (size_t i = 1; i < vec.size(); i++) {
os << ' ' << vec[i];
}
os << '\n';
return os;
}
template<class v>
auto operator>>(istream &is, vector<v> &vec)->istream& {
for (auto &i : vec) {
is >> i;
}
return is;
}
template<class v>
auto operator<<(ostream &os, const vector<vector<v>> &vec)->ostream& {
for (auto &i : vec) {
os << i[0];
for (size_t j = 1; j < i.size(); j++) {
os << ' ' << i[j];
}
os << '\n';
}
return os;
}
template<class v>
auto operator>>(istream &is, vector<vector<v>> &vec)->istream& {
for (auto &i : vec) {
for (auto &j : i) {
is >> j;
}
}
return is;
}
int main()
{
ios::sync_with_stdio(false);
cin.tie(nullptr);
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
vi fds(n);
cin >> fds;
int prev = n;
n++;
fds.push_back(0);
while (__builtin_popcount(n) != 1) {
n++;
fds.push_back(0);
}
vvi segm(n * 2);
function<void(int, int, int)> build = [&](int i, int l, int r) {
if (l == r) {
segm[i] = {fds[i - n]};
return;
}
int mid = (l + r) >> 1;
build(i * 2, l, mid);
build(i * 2 + 1, mid + 1, r);
merge(all(segm[i * 2]), all(segm[i * 2 + 1]), back_inserter(segm[i]));
};
build(1, 0, n - 1);
function<int(int, int, int, int, int, int)> querym = [&](int i, int l, int r, int tl, int tr, int v) {
if (l > tr || r < tl) {
return 0;
}
if (l >= tl && r <= tr) {
auto upper = upper_bound(all(segm[i]), v);
return (int)(segm[i].end() - upper);
}
int mid = (l + r) >> 1;
return querym(i * 2, l, mid, tl, tr, v) + querym(i * 2 + 1, mid + 1, r, tl, tr, v);
};
vi seg(n * 2, -1);
auto update = [&](int i, int v) {
i += n;
seg[i] = v;
for (i >>= 1; i > 0; i >>= 1) {
seg[i] = min(seg[i * 2], seg[i * 2 + 1]);
}
};
function<int(int, int, int, int, int)> query = [&](int i, int l, int r, int tl, int tr) {
int oo = INT32_MAX >> 1;
if (l > tr || r < tl) {
return oo;
}
if (l >= tl && r <= tr) {
return seg[i];
}
int mid = (l + r) >> 1;
return min(query(i * 2, l, mid, tl, tr), query(i * 2 + 1, mid + 1, r, tl, tr));
};
vi ans(prev);
rep(i, prev) {
update(fds[i], i);
int mex = 0;
int ans = 0;
while (mex <= n) {
int minimal = query(1, 0, n - 1, 0, mex);
int tmp = querym(1, 0 , n - 1, minimal, i, mex);
if (tmp >= ans) {
ans = tmp;
mex++;
continue;
}
break;
}
cout << ans << " \n"[i == prev - 1];
}
}
}