Codeforces-solutions/Codeforces Round 991 (Div. 3)/F. Maximum modulo equality.cpp
2025-09-12 14:50:25 -03:00

107 lines
2.2 KiB
C++

/* Problem URL: https://codeforces.com/contest/2050/problem/F */
#include <bits/stdc++.h>
using namespace std;
#define V vector
#define rmin(a, b) a = min(a, b)
#define rmax(a, b) a = max(a, b)
#define rep(i, lim) for (size_t i = 0; i < (lim); i++)
#define nrep(i, s, lim) for (size_t i = s; i < (lim); i++)
#define repv(i, v) for (auto &i : (v))
#define fillv(v) for (auto &itr_ : (v)) { cin >> itr_; }
#define sortv(v) sort(v.begin(), v.end())
#define all(v) (v).begin(), (v).end()
using vi = vector<int>;
using vvi = vector<vi>;
using vvvi = vector<vvi>;
using vvvvi = vector<vvvi>;
using ll = long long;
using vl = vector<ll>;
using vvl = vector<vl>;
using vvvl = vector<vvl>;
using vvvvl = vector<vvvl>;
template<class v>
auto operator<<(ostream &os, const vector<v> &vec)->ostream& {
os << vec[0];
for (size_t i = 1; i < vec.size(); i++) {
os << ' ' << vec[i];
}
os << '\n';
return os;
}
template<class v>
auto operator>>(istream &is, vector<v> &vec)->istream& {
for (auto &i : vec) {
is >> i;
}
return is;
}
template<class v>
auto operator<<(ostream &os, const vector<vector<v>> &vec)->ostream& {
for (auto &i : vec) {
os << i[0];
for (size_t j = 1; j < i.size(); j++) {
os << ' ' << i[j];
}
os << '\n';
}
return os;
}
template<class v>
auto operator>>(istream &is, vector<vector<v>> &vec)->istream& {
for (auto &i : vec) {
for (auto &j : i) {
is >> j;
}
}
return is;
}
int dp(int i, int j, int k, string &a, string &b, string &c)
{
if (i >= a.size() || j >= b.size() || k >= c.size()) {
return 0;
}
if (a[i] != c[k] && b[j] != c[k]) {
return min(dp(i + 1, j, k + 1, a, b, c), dp(i, j + 1, k, a, b, c)) + 1;
}
if (a[i] == b[j]) {
return min(dp(i + 1, j, k + 1, a, b, c), dp(i, j + 1, k, a, b, c));
}
if (a[i] == c[k]) {
return dp(i + 1, j, k + 1, a, b, c);
}
return dp(i, j + 1, k + 1, a, b, c);
}
int main()
{
ios::sync_with_stdio(false);
cin.tie(nullptr);
int t;
cin >> t;
while (t--) {
string a, b, c;
cin >> a >> b >> c;
cout << dp(0, 0, 0, a, b, c) << '\n';
}
}