233 lines
4.5 KiB
C++
233 lines
4.5 KiB
C++
/* Problem URL: https://codeforces.com/edu/course/2/lesson/2/3/practice/contest/269118/problem/B */
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#include <bits/stdc++.h>
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#include <ext/pb_ds/assoc_container.hpp>
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#include <ext/pb_ds/tree_policy.hpp>
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using namespace std;
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using namespace __gnu_pbds;
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template <class T, class comp = less<>>
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using ordered_set = tree<T, null_type , comp , rb_tree_tag , tree_order_statistics_node_update>;
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#define V vector
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#define rmin(a, b) a = min(a, b)
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#define rmax(a, b) a = max(a, b)
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#define rep(i, lim) for (int i = 0; i < (lim); i++)
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#define nrep(i, s, lim) for (int i = s; i < (lim); i++)
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#define repv(i, v) for (auto &i : (v))
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#define fillv(v) for (auto &itr_ : (v)) { cin >> itr_; }
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#define sortv(v) sort(v.begin(), v.end())
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#define all(v) (v).begin(), (v).end()
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using vi = vector<int>;
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using vvi = vector<vi>;
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using vvvi = vector<vvi>;
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using vvvvi = vector<vvvi>;
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using ll = long long;
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using vl = vector<ll>;
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using vvl = vector<vl>;
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using vvvl = vector<vvl>;
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using vvvvl = vector<vvvl>;
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template<class v>
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auto operator<<(ostream &os, const vector<v> &vec)->ostream& {
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os << vec[0];
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for (size_t i = 1; i < vec.size(); i++) {
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os << ' ' << vec[i];
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}
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os << '\n';
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return os;
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}
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template<class v>
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auto operator>>(istream &is, vector<v> &vec)->istream& {
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for (auto &i : vec) {
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is >> i;
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}
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return is;
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}
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template<class v>
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auto operator<<(ostream &os, const vector<vector<v>> &vec)->ostream& {
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for (auto &i : vec) {
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os << i[0];
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for (size_t j = 1; j < i.size(); j++) {
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os << ' ' << i[j];
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}
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os << '\n';
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}
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return os;
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}
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template<class v>
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auto operator>>(istream &is, vector<vector<v>> &vec)->istream& {
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for (auto &i : vec) {
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for (auto &j : i) {
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is >> j;
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}
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}
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return is;
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}
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const int oo = INT32_MAX >> 1;
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const ll OO = INT64_MAX >> 1;
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void pre()
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{
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}
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#define TEST 0
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void solve()
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{
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string s;
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cin >> s;
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s.push_back('$');
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int n = s.size();
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vi cnt(max(n, 256));
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vi p(n);
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rep(i, n) {
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cnt[s[i]]++;
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}
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nrep(i, 1, cnt.size()) {
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cnt[i] += cnt[i - 1];
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}
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rep(i, n) {
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cnt[s[i]]--;
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p[cnt[s[i]]] = i;
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}
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vi c(n);
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nrep(i, 1, n) {
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c[p[i]] = c[p[i - 1]];
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if (s[p[i]] != s[p[i - 1]]) {
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c[p[i]]++;
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}
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}
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vi cn(n);
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vi pn(n);
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for (int j = 0; (1 << j) < n; j++) {
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rep(i, n) {
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pn[i] = p[i] - (1 << j);
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pn[i] += n * (pn[i] < 0);
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}
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fill(all(cnt), 0);
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rep(i, n) {
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cnt[c[pn[i]]]++;
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}
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nrep(i, 1, cnt.size()) {
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cnt[i] += cnt[i - 1];
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}
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for (int i = n - 1; i >= 0; i--) {
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cnt[c[pn[i]]]--;
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p[cnt[c[pn[i]]]] = pn[i];
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}
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cn[p[0]] = 0;
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nrep(i, 1, n) {
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pair<int, int> cur = {c[p[i]], c[(p[i] + (1 << j)) % n]};
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pair<int, int> prev = {c[p[i - 1]], c[(p[i - 1] + (1 << j)) % n]};
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cn[p[i]] = cn[p[i - 1]];
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if (cur != prev) {
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cn[p[i]]++;
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}
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}
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swap(cn, c);
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}
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int q;
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cin >> q;
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while (q--) {
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string a;
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cin >> a;
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auto comp = [&](int pos) {
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int i = 0;
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while (i < a.size() && i < s.size() && a[i] == s[(i + p[pos]) % n]) {
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i++;
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}
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if (i == a.size()) { // equal
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return 0;
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}
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if (i == s.size() || a[i] > s[(i + p[pos]) % n]) { // bigger
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return 1;
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}
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return -1; // lesser
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};
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int low = 0;
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int high = n - 1;
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int ans1 = n;
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while (low <= high) {
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int mid = (low + high) >> 1;
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int test = comp(mid);
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if (test <= 0) {
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ans1 = mid;
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high = mid - 1;
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continue;
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}
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low = mid + 1;
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}
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low = 0;
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high = n - 1;
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int ans2 = n;
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while (low <= high) {
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int mid = (low + high) >> 1;
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int test = comp(mid);
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if (test < 0) {
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ans2 = mid;
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high = mid - 1;
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continue;
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}
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low = mid + 1;
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}
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cout << ans2 - ans1 << '\n';
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}
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}
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int main()
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{
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ios::sync_with_stdio(false);
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cin.tie(nullptr);
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pre();
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int t;
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(TEST && cin >> t) || (t = 1);
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while (t--) {
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solve();
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}
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}
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