Codeforces-solutions/think-cell Round 1/C. Lexicographically Largest.cpp

213 lines
3.8 KiB
C++

/* Problem URL: https://codeforces.com/problemset/problem/1930/C */
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
template <class T, class comp = less<>>
using ordered_set = tree<T, null_type , comp , rb_tree_tag , tree_order_statistics_node_update>;
#define V vector
#define rmin(a, b) a = min(a, b)
#define rmax(a, b) a = max(a, b)
#define rep(i, lim) for (int i = 0; i < (lim); i++)
#define nrep(i, s, lim) for (int i = s; i < (lim); i++)
#define repv(i, v) for (auto &i : (v))
#define fillv(v) for (auto &itr_ : (v)) { cin >> itr_; }
#define sortv(v) sort(v.begin(), v.end())
#define all(v) (v).begin(), (v).end()
using vi = vector<int>;
using vvi = vector<vi>;
using vvvi = vector<vvi>;
using vvvvi = vector<vvvi>;
using ll = long long;
using vl = vector<ll>;
using vvl = vector<vl>;
using vvvl = vector<vvl>;
using vvvvl = vector<vvvl>;
template<class v>
auto operator<<(ostream &os, const vector<v> &vec)->ostream& {
os << vec[0];
for (size_t i = 1; i < vec.size(); i++) {
os << ' ' << vec[i];
}
os << '\n';
return os;
}
template<class v>
auto operator>>(istream &is, vector<v> &vec)->istream& {
for (auto &i : vec) {
is >> i;
}
return is;
}
template<class v>
auto operator<<(ostream &os, const vector<vector<v>> &vec)->ostream& {
for (auto &i : vec) {
os << i[0];
for (size_t j = 1; j < i.size(); j++) {
os << ' ' << i[j];
}
os << '\n';
}
return os;
}
template<class v>
auto operator>>(istream &is, vector<vector<v>> &vec)->istream& {
for (auto &i : vec) {
for (auto &j : i) {
is >> j;
}
}
return is;
}
const int oo = INT32_MAX >> 1;
const ll OO = INT64_MAX >> 1;
void pre()
{
}
#define TEST 1
struct dymseg {
struct node {
int left;
int right;
int val;
};
V<node> seg;
dymseg(int n) {
seg.emplace_back(-1, -1, 0);
}
int create_node() {
seg.emplace_back(-1, -1, 0);
return seg.size() - 1;
}
void create_nodes(int i) {
if (seg[i].left == -1) {
seg[i].left = create_node();
}
if (seg[i].right == -1) {
seg[i].right = create_node();
}
}
void update(int i, ll l, ll r, int p) {
if (l == r) {
seg[i].val = 1;
return;
}
seg[i].val++;
create_nodes(i);
ll mid = (l + r) >> 1;
if (mid >= p) {
update(seg[i].left, l, mid, p);
return;
}
update(seg[i].right, mid + 1, r, p);
}
ll tl, tr;
ll query(int i, ll l, ll r) {
if (l > tr || r < tl || seg[i].val == r - l + 1) {
return -1;
}
if (l == r) {
return l;
}
ll mid = (l + r) >> 1;
create_nodes(i);
int ans = query(seg[i].right, mid + 1, r);
if (ans != -1) {
return ans;
}
return query(seg[i].left, l, mid);
}
public:
void update(ll p) {
update(0, 0, 1LL << 31, p);
}
ll query(ll l, ll r) {
tl = l;
tr = r;
return query(0, 0, 1LL << 31);
}
};
void solve()
{
int n;
cin >> n;
vl a(n);
cin >> a;
dymseg seg(n);
set<ll, greater<>> ans;
rep(i, n) {
ll choice = seg.query(a[i], a[i] + i + 1);
if (choice == -1) {
continue;
}
ans.insert(choice);
seg.update(choice);
}
repv(i, ans) {
cout << i << ' ';
}
cout << '\n';
}
int main()
{
ios::sync_with_stdio(false);
cin.tie(nullptr);
pre();
int t;
(TEST && cin >> t) || (t = 1);
while (t--) {
solve();
}
}