182 lines
4.3 KiB
C++
182 lines
4.3 KiB
C++
/* Problem URL: https://codeforces.com/edu/course/2/lesson/5/4/practice/contest/280801/problem/E */
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#include <bits/stdc++.h>
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#include <ext/pb_ds/assoc_container.hpp>
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#include <ext/pb_ds/tree_policy.hpp>
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using namespace std;
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using namespace __gnu_pbds;
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template <class T, class comp = less<>>
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using ordered_set = tree<T, null_type , comp , rb_tree_tag , tree_order_statistics_node_update>;
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#define V vector
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#define rmin(a, b) a = min(a, b)
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#define rmax(a, b) a = max(a, b)
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#define rep(i, lim) for (int i = 0; i < (lim); i++)
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#define nrep(i, s, lim) for (int i = s; i < (lim); i++)
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#define repv(i, v) for (auto &i : (v))
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#define fillv(v) for (auto &itr_ : (v)) { cin >> itr_; }
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#define sortv(v) sort(v.begin(), v.end())
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#define all(v) (v).begin(), (v).end()
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using vi = vector<int>;
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using vvi = vector<vi>;
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using vvvi = vector<vvi>;
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using vvvvi = vector<vvvi>;
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using ll = long long;
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using vl = vector<ll>;
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using vvl = vector<vl>;
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using vvvl = vector<vvl>;
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using vvvvl = vector<vvvl>;
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template<class v>
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auto operator<<(ostream &os, const vector<v> &vec)->ostream& {
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os << vec[0];
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for (size_t i = 1; i < vec.size(); i++) {
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os << ' ' << vec[i];
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}
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os << '\n';
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return os;
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}
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template<class v>
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auto operator>>(istream &is, vector<v> &vec)->istream& {
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for (auto &i : vec) {
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is >> i;
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}
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return is;
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}
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template<class v>
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auto operator<<(ostream &os, const vector<vector<v>> &vec)->ostream& {
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for (auto &i : vec) {
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os << i[0];
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for (size_t j = 1; j < i.size(); j++) {
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os << ' ' << i[j];
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}
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os << '\n';
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}
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return os;
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}
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template<class v>
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auto operator>>(istream &is, vector<vector<v>> &vec)->istream& {
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for (auto &i : vec) {
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for (auto &j : i) {
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is >> j;
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}
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}
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return is;
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}
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int main()
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{
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ios::sync_with_stdio(false);
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cin.tie(nullptr);
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int n, k;
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cin >> n >> k;
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int prev = n;
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if (n > 1) {
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n = 1 << (32 - __builtin_clz(n - 1));
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}
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vl seg(n * 2);
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V<pair<ll, ll>> lazy(n * 2, {0, 1e5});
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V<bool> upd(n * 2);
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auto propagate = [&](int i) {
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if (!upd[i]) {
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return;
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}
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upd[i] = false;
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rmax(seg[i], lazy[i].first);
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rmin(seg[i], lazy[i].second);
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if (i < n) {
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rmax(lazy[i * 2].first, lazy[i].first);
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rmin(lazy[i * 2].second, lazy[i].second);
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if (lazy[i * 2].first > lazy[i * 2].second) {
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if (lazy[i * 2].first == lazy[i].first) {
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lazy[i * 2].second = lazy[i * 2].first;
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} else {
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lazy[i * 2].first = lazy[i * 2].second;
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}
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}
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upd[i * 2] = true;
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rmax(lazy[i * 2 + 1].first, lazy[i].first);
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rmin(lazy[i * 2 + 1].second, lazy[i].second);
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if (lazy[i * 2 + 1].first > lazy[i * 2 + 1].second) {
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if (lazy[i * 2 + 1].first == lazy[i].first) {
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lazy[i * 2 + 1].second = lazy[i * 2 + 1].first;
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} else {
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lazy[i * 2 + 1].first = lazy[i * 2 + 1].first;
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}
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}
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upd[i * 2 + 1] = true;
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}
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lazy[i] = {0, 1e5};
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};
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function<void(int, int, int, int, int, int, ll)> update = [&](int i, int l, int r, int tl, int tr, int t, ll v) {
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propagate(i);
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if (l > tr || r < tl) {
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return;
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}
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if (l >= tl && r <= tr) {
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if (t) {
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lazy[i].second = v;
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} else {
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lazy[i].first = v;
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}
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upd[i] = true;
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propagate(i);
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return;
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}
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int mid = (l + r) >> 1;
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update(i * 2, l, mid, tl, tr, t, v);
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update(i * 2 + 1, mid + 1, r, tl, tr, t, v);
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};
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function<ll(int, int, int, int)> query = [&](int i, int l, int r, int t) {
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propagate(i);
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if (i >= n) {
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return seg[i];
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}
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int mid = (l + r) >> 1;
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if (mid >= t) {
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return query(i * 2, l, mid, t);
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}
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return query(i * 2 + 1, mid + 1, r, t);
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};
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while (k--) {
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int op, l, r, h;
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cin >> op >> l >> r >> h;
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update(1, 0, n - 1, l, r, op - 1, h);
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}
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rep(i, prev) {
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cout << query(1, 0, n - 1, i) << '\n';
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}
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}
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