/* Problem URL: https://codeforces.com/contest/1006/problem/F */ #include using namespace std; #define V vector #define rmin(a, b) a = min(a, b) #define rmax(a, b) a = max(a, b) #define rep(i, lim) for (int i = 0; i < (lim); i++) #define nrep(i, s, lim) for (int i = s; i < (lim); i++) #define repv(i, v) for (auto &i : (v)) #define fillv(v) for (auto &itr_ : (v)) { cin >> itr_; } #define sortv(v) sort(v.begin(), v.end()) #define all(v) (v).begin(), (v).end() using vi = vector; using vvi = vector; using vvvi = vector; using vvvvi = vector; using ll = long long; using vl = vector; using vvl = vector; using vvvl = vector; using vvvvl = vector; template auto operator<<(ostream &os, const vector &vec)->ostream& { os << vec[0]; for (size_t i = 1; i < vec.size(); i++) { os << ' ' << vec[i]; } os << '\n'; return os; } template auto operator>>(istream &is, vector &vec)->istream& { for (auto &i : vec) { is >> i; } return is; } template auto operator<<(ostream &os, const vector> &vec)->ostream& { for (auto &i : vec) { os << i[0]; for (size_t j = 1; j < i.size(); j++) { os << ' ' << i[j]; } os << '\n'; } return os; } template auto operator>>(istream &is, vector> &vec)->istream& { for (auto &i : vec) { for (auto &j : i) { is >> j; } } return is; } int main() { ios::sync_with_stdio(false); cin.tie(nullptr); int n, m; ll k; cin >> n >> m >> k; vvl fds(n, vl(m)); cin >> fds; int mid = n / 2; if (n == 1) { ll ans = 0; repv(i, fds[0]) { ans ^= i; } cout << (ans == k) << '\n'; return 0; } vvl ans1(m); function calc1 = [&](int i, int j, ll now) { if (i >= n - mid - 1) { ans1[j].push_back(now); } if (j < m - 1) { calc1(i, j + 1, now ^ fds[i][j + 1]); } if (i < n - mid - 1) { calc1(i + 1, j, now ^ fds[i + 1][j]); } }; calc1(0, 0, fds[0][0]); rep(j, m) { sortv(ans1[j]); } ll ans = 0; function calc2 = [&](int i, int j, ll now, int t) { if (i == n - 1 && j == m - 1) { auto lower = lower_bound(all(ans1[t]), k ^ now); auto upper = upper_bound(all(ans1[t]), k ^ now); ans += upper - lower; return; } if (i < n - 1) { calc2(i + 1, j, now ^ fds[i + 1][j], t); } if (j < m - 1) { calc2(i, j + 1, now ^ fds[i][j + 1], t); } }; rep(j, m) { calc2(n - mid, j, fds[n - mid][j], j); } cout << ans << '\n'; }