/* Problem URL: https://codeforces.com/contest/990/problem/D */ #include #include #include using namespace std; using namespace __gnu_pbds; template > using ordered_set = tree; #define V vector #define rmin(a, b) a = min(a, b) #define rmax(a, b) a = max(a, b) #define rep(i, lim) for (int i = 0; i < (lim); i++) #define nrep(i, s, lim) for (int i = s; i < (lim); i++) #define repv(i, v) for (auto &i : (v)) #define fillv(v) for (auto &itr_ : (v)) { cin >> itr_; } #define sortv(v) sort(v.begin(), v.end()) #define all(v) (v).begin(), (v).end() using vi = vector; using vvi = vector; using vvvi = vector; using vvvvi = vector; using ll = long long; using vl = vector; using vvl = vector; using vvvl = vector; using vvvvl = vector; template auto operator<<(ostream &os, const vector &vec)->ostream& { os << vec[0]; for (size_t i = 1; i < vec.size(); i++) { os << ' ' << vec[i]; } os << '\n'; return os; } template auto operator>>(istream &is, vector &vec)->istream& { for (auto &i : vec) { is >> i; } return is; } template auto operator<<(ostream &os, const vector> &vec)->ostream& { for (auto &i : vec) { os << i[0]; for (size_t j = 1; j < i.size(); j++) { os << ' ' << i[j]; } os << '\n'; } return os; } template auto operator>>(istream &is, vector> &vec)->istream& { for (auto &i : vec) { for (auto &j : i) { is >> j; } } return is; } int main() { ios::sync_with_stdio(false); cin.tie(nullptr); int n, a, b; cin >> n >> a >> b; if (n == 1) { cout << "YES\n0\n"; return 0; } if (n == 2) { if (a == b) { cout << "NO\n"; } else { cout << "YES\n"; if (a == 1) { cout << "01\n10\n"; } else { cout << "00\n00\n"; } } return 0; } if (a != 1 && b != 1) { cout << "NO\n"; return 0; } if (n == 3 && max(a, b) == 1) { cout << "NO\n"; return 0; } bool inv = false; if (b == 1) { swap(a, b); inv = true; } cout << "YES\n"; vvi adj(n, vi(n)); if (b == 1) { nrep(i, 1, n - 1) { adj[0][i] = 1; adj[i][0] = 1; } adj[n - 1][n - 2] = 1; adj[n - 2][n - 1] = 1; repv(i, adj) { repv(j, i) { cout << j; } cout << '\n'; } return 0; } rep(i, b - 1) { nrep(j, i + 1, n) { adj[i][j] = 1; adj[j][i] = 1; } } if (inv) { rep(i, n) { rep(j, n) { if (i == j) { continue; } adj[i][j] ^= 1; } } } repv(i, adj) { repv(j, i) { cout << j; } cout << '\n'; } }