/* Problem URL: https://codeforces.com/contest/2132/problem/E */ #include #include #include using namespace std; using namespace __gnu_pbds; template > using ordered_set = tree; #define V vector #define rmin(a, b) a = min(a, b) #define rmax(a, b) a = max(a, b) #define rep(i, lim) for (int i = 0; i < (lim); i++) #define nrep(i, s, lim) for (int i = s; i < (lim); i++) #define repv(i, v) for (auto &i : (v)) #define fillv(v) for (auto &itr_ : (v)) { cin >> itr_; } #define sortv(v) sort(v.begin(), v.end()) #define all(v) (v).begin(), (v).end() using vi = vector; using vvi = vector; using vvvi = vector; using vvvvi = vector; using ll = long long; using vl = vector; using vvl = vector; using vvvl = vector; using vvvvl = vector; template auto operator<<(ostream &os, const vector &vec)->ostream& { os << vec[0]; for (size_t i = 1; i < vec.size(); i++) { os << ' ' << vec[i]; } os << '\n'; return os; } template auto operator>>(istream &is, vector &vec)->istream& { for (auto &i : vec) { is >> i; } return is; } template auto operator<<(ostream &os, const vector> &vec)->ostream& { for (auto &i : vec) { os << i[0]; for (size_t j = 1; j < i.size(); j++) { os << ' ' << i[j]; } os << '\n'; } return os; } template auto operator>>(istream &is, vector> &vec)->istream& { for (auto &i : vec) { for (auto &j : i) { is >> j; } } return is; } int main() { ios::sync_with_stdio(false); cin.tie(nullptr); int t; cin >> t; while (t--) { int n, m, q; cin >> n >> m >> q; vl af(n); vl bf(m); cin >> af >> bf; vl a(n + 1); vl b(m + 1); sort(all(af), greater<>()); sort(all(bf), greater<>()); rep(i, n) { a[i + 1] = a[i] + af[i]; } rep(i, m) { b[i + 1] = b[i] + bf[i]; } while (q--) { int x, y, z; cin >> x >> y >> z; ll ans = 0; ll low = 0; ll high = min(x, z); while ((high - low) >= 3) { ll third = (high - low) / 3; ll mid1 = low + third; ll mid2 = high - third; ll ans1 = a[mid1] + b[max(min(z - mid1, (ll)y), 0LL)]; ll ans2 = a[mid2] + b[max(min(z - mid2, (ll)y), 0LL)]; ans = max({ans, ans1, ans2}); if (ans1 > ans2) { high = mid2 - 1; continue; } if (ans2 > ans1) { low = mid1 + 1; continue; } low = mid1 + 1; high = mid2 - 1; } nrep(i, low, high + 1) { rmax(ans, a[i] + b[max(min(z - (ll)i, (ll)y), 0LL)]); } cout << ans << '\n'; } } }