/* Problem URL: https://codeforces.com/problemset/problem/1912/K */ #include #include #include using namespace std; using namespace __gnu_pbds; template > using ordered_set = tree; #define V vector #define rmin(a, b) a = min(a, b) #define rmax(a, b) a = max(a, b) #define rep(i, lim) for (int i = 0; i < (lim); i++) #define nrep(i, s, lim) for (int i = s; i < (lim); i++) #define repv(i, v) for (auto &i : (v)) #define fillv(v) for (auto &itr_ : (v)) { cin >> itr_; } #define sortv(v) sort(v.begin(), v.end()) #define all(v) (v).begin(), (v).end() using vi = vector; using vvi = vector; using vvvi = vector; using vvvvi = vector; using ll = long long; using vl = vector; using vvl = vector; using vvvl = vector; using vvvvl = vector; template auto operator<<(ostream &os, const vector &vec)->ostream& { os << vec[0]; for (size_t i = 1; i < vec.size(); i++) { os << ' ' << vec[i]; } os << '\n'; return os; } template auto operator>>(istream &is, vector &vec)->istream& { for (auto &i : vec) { is >> i; } return is; } template auto operator<<(ostream &os, const vector> &vec)->ostream& { for (auto &i : vec) { os << i[0]; for (size_t j = 1; j < i.size(); j++) { os << ' ' << i[j]; } os << '\n'; } return os; } template auto operator>>(istream &is, vector> &vec)->istream& { for (auto &i : vec) { for (auto &j : i) { is >> j; } } return is; } const int oo = INT32_MAX >> 1; const ll OO = INT64_MAX >> 1; const ll mod = 998244353; constexpr int MAXN = 2e5 + 10; ll fact[MAXN]; ll inv[MAXN]; ll invf[MAXN]; ll comb(ll n, ll k) { return fact[n] * invf[k] % mod * invf[n - k] % mod; } void pre() { fact[0] = 1; nrep(i, 1, MAXN) { fact[i] = fact[i - 1] * i % mod; } inv[1] = 1; nrep(i, 2, MAXN) { inv[i] = (mod - mod / i) * inv[mod % i] % mod; } invf[0] = 1; nrep(i, 1, MAXN) { invf[i] = invf[i - 1] * inv[i] % mod; } } #define TEST 0 void solve() { int n; cin >> n; vl a(n); ll c = 0; repv(i, a) { cin >> i; c += ~i & 1; } ll ans = 0; nrep(i, 3, c + 1) { (ans += comb(c, i)) %= mod; } int seq[] = {1, 0, 1}; vvvl memo(n, vvl(3, vl(2, -1))); auto init = [&]() { rep(i, n) { rep(j, 3) { rep(k, 2) { memo[i][j][k] = -1; } } } }; function dp = [&](int i, int c, int val) { if (i >= n) { return 0LL; } ll &ans = memo[i][c][val]; if (ans != -1) { return ans; } ans = 0; if (seq[c] == (a[i] & 1)) { (ans += dp(i + 1, (c + 1) % 3, val || (c == 2)) + (val || (c == 2))) %= mod; } (ans += dp(i + 1, c, val)) %= mod; return ans; }; (ans += dp(0, 0, 0)) %= mod; seq[0] = 0; seq[1] = 1; init(); (ans += dp(0, 0, 0)) %= mod; seq[0] = 1; seq[2] = 0; init(); (ans += dp(0, 0, 0)) %= mod; cout << ans << '\n'; } int main() { ios::sync_with_stdio(false); cin.tie(nullptr); pre(); int t; (TEST && cin >> t) || (t = 1); while (t--) { solve(); } }