CSES-solutions/CSES Problem Set/Longest Common Subsequence.cpp
Segcolt 8b03716512 Add a lot more of my solutions.
I don't remember which ones doesn't pass though
2025-09-12 14:51:10 -03:00

127 lines
2.4 KiB
C++

/* Problem URL: https://cses.fi/problemset/task/3403 */
#include <bits/stdc++.h>
using namespace std;
#define V vector
#define rmin(a, b) a = min(a, b)
#define rmax(a, b) a = max(a, b)
#define rep(i, lim) for (int i = 0; i < (lim); i++)
#define nrep(i, s, lim) for (int i = s; i < (lim); i++)
#define repv(i, v) for (auto &i : (v))
#define fillv(v) for (auto &itr_ : (v)) { cin >> itr_; }
#define sortv(v) sort(v.begin(), v.end())
#define all(v) (v).begin(), (v).end()
using vi = vector<int>;
using vvi = vector<vi>;
using vvvi = vector<vvi>;
using vvvvi = vector<vvvi>;
using ll = long long;
using vl = vector<ll>;
using vvl = vector<vl>;
using vvvl = vector<vvl>;
using vvvvl = vector<vvvl>;
template<class v>
auto operator<<(ostream &os, const vector<v> &vec)->ostream& {
os << vec[0];
for (size_t i = 1; i < vec.size(); i++) {
os << ' ' << vec[i];
}
os << '\n';
return os;
}
template<class v>
auto operator>>(istream &is, vector<v> &vec)->istream& {
for (auto &i : vec) {
is >> i;
}
return is;
}
template<class v>
auto operator<<(ostream &os, const vector<vector<v>> &vec)->ostream& {
for (auto &i : vec) {
os << i[0];
for (size_t j = 1; j < i.size(); j++) {
os << ' ' << i[j];
}
os << '\n';
}
return os;
}
template<class v>
auto operator>>(istream &is, vector<vector<v>> &vec)->istream& {
for (auto &i : vec) {
for (auto &j : i) {
is >> j;
}
}
return is;
}
int main()
{
ios::sync_with_stdio(false);
cin.tie(nullptr);
int n, m;
cin >> n >> m;
vi a(n);
vi b(m);
cin >> a >> b;
vvi dp(n + 1, vi(m + 1));
nrep(i, 1, n + 1) {
nrep(j, 1, m + 1) {
if (a[i - 1] == b[j - 1]) {
dp[i][j] = dp[i - 1][j - 1] + 1;
continue;
}
dp[i][j] = max(dp[i - 1][j], dp[i][j - 1]);
}
}
cout << dp[n][m] << '\n';
// if (dp[n][m] == 0) {
// return 0;
// }
vi ans(dp[n][m]);
int act = dp[n][m] - 1;
int i = n;
int j = m;
while (i > 0 && j > 0) {
if (a[i - 1] == b[j - 1]) {
ans[act] = a[i - 1];
i--;
j--;
act--;
continue;
}
if (dp[i - 1][j] > dp[i][j - 1]) {
i--;
continue;
}
j--;
}
cout << ans;
}