/* Problem URL: https://cses.fi/problemset/task/2220 */ #include using namespace std; #define V vector #define rmin(a, b) a = min(a, b) #define rmax(a, b) a = max(a, b) #define rep(i, lim) for (size_t i = 0; i < (lim); i++) #define nrep(i, s, lim) for (size_t i = s; i < (lim); i++) #define repv(i, v) for (auto &i : (v)) #define fillv(v) for (auto &itr_ : (v)) { cin >> itr_; } #define sortv(v) sort(v.begin(), v.end()) #define all(v) (v).begin(), (v).end() using vi = vector; using vvi = vector; using vvvi = vector; using vvvvi = vector; using ll = long long; using vl = vector; using vvl = vector; using vvvl = vector; using vvvvl = vector; template auto operator<<(ostream &os, const vector &vec)->ostream& { os << vec[0]; for (size_t i = 1; i < vec.size(); i++) { os << ' ' << vec[i]; } os << '\n'; return os; } template auto operator>>(istream &is, vector &vec)->istream& { for (auto &i : vec) { is >> i; } return is; } template auto operator<<(ostream &os, const vector> &vec)->ostream& { for (auto &i : vec) { os << i[0]; for (size_t j = 1; j < i.size(); j++) { os << ' ' << i[j]; } os << '\n'; } return os; } template auto operator>>(istream &is, vector> &vec)->istream& { for (auto &i : vec) { for (auto &j : i) { is >> j; } } return is; } vvvvl memo; void dec(int i, string &a) { if (a[i] == '0') { a[i] = '9'; dec(i - 1, a); return; } a[i] -= 1; } ll dp(int i, int prev, int started, int under, string &a) { if (i >= memo.size()) { return 1; } ll &ans = memo[i][prev][started][under]; if (ans != -1) { return ans; } ans = 0; for (char j = under ? 9 : a[i] - '0'; j >= 0; j--) { if (j != prev || !started) { ans += dp(i + 1, j, j != 0 || started, j < a[i] - '0' || under, a); } } return ans; } int main() { ios::sync_with_stdio(false); cin.tie(nullptr); ll ai, bi; cin >> ai >> bi; string a = to_string(ai); string b = to_string(bi); memo.assign(b.size(), vvvl(10, vvl(2, vl(2, -1)))); ll ans = dp(0, 0, 0, 0, b); if (a != "0") { dec(a.size() - 1, a); memo.assign(a.size(), vvvl(10, vvl(2, vl(2, -1)))); ans -= dp(0, 0, 0, 0, a); } cout << ans << '\n'; }